What are the solutions to the equation w^2+10w+25=0 ?

The solutions to the equation w^2+10w+25=0 are w=-5

Find the zeros of w^2+10w+25=0

The zeros of w^2+10w+25=0 are w=-5

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w^{2} + 10 w + 25 = 0

w = - 5

Solution steps

w^{2} + 10 w + 25 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

w_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

w = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

w = - 5

The solution to the quadratic equation is:

w = - 5

4 x - 3 > 13

x^{2} + x - 2 < 0

\frac{y ^{\frac{5}{4}}}{y ^{\frac{1}{4}}}

22 x y - 15 x^{2} - 8 y^{2}

What are the solutions to the equation w^2+10w+25=0 ?
The solutions to the equation w^2+10w+25=0 are w=-5
Find the zeros of w^2+10w+25=0
The zeros of w^2+10w+25=0 are w=-5