What is |((2x^2-4))/3 |>= 2x^2 ?

The solution to |((2x^2-4))/3 |>= 2x^2 is -sqrt(1/2)<= x<= sqrt(1/2)

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|((2x^2-4))/3 |>= 2x^2

\frac{( 2 x ^{2} - 4 )}{3} \geq 2 x^{2}

- \frac{1}{2} \leq x \leq \frac{1}{2}

Solution steps

\frac{2 x ^{2} - 4}{3} \geq 2 x^{2}

Find positive and negative intervals

x \leq - 2, - 2 < x < 2, x \geq 2

Solve the inequality for each interval

No Solution or - \frac{1}{2} \leq x \leq \frac{1}{2}

Merge Overlapping Intervals

- \frac{1}{2} \leq x \leq \frac{1}{2}

∣ x + 1 ∣ < ∣ 2 x - 1 ∣

\frac{( 5 x + 5 )}{10} \geq 5

x^{2} - 2 x - 3 > 1

∣ x - 2 ∣ + ∣ x - 3 ∣ + ∣ x - 4 ∣ > 6

∣ 5 x - 2 ∣ < 3 x + 4

What is |((2x^2-4))/3 |>= 2x^2 ?
The solution to |((2x^2-4))/3 |>= 2x^2 is -sqrt(1/2)<= x<= sqrt(1/2)