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Popular >

|-x^2-9x-7|>= 1

Solution

- x^{2} - 9 x - 7 \geq 1

Solution

x \leq \frac{- 57 - 9}{2} or - 8 \leq x \leq - 1 or x \geq \frac{57 - 9}{2}

+2

Solution steps

- x^{2} - 9 x - 7 \geq 1

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

- x^{2} - 9 x - 7 \leq - 1 or - x^{2} - 9 x - 7 \geq 1

- x^{2} - 9 x - 7 \leq - 1 or - x^{2} - 9 x - 7 \geq 1

(x \leq \frac{- 57 - 9}{2} or x \geq \frac{57 - 9}{2}) or - 8 \leq x \leq - 1

Merge Overlapping Intervals

x \leq \frac{- 57 - 9}{2} or - 8 \leq x \leq - 1 or x \geq \frac{57 - 9}{2}

Popular Examples

|x-2|>2+x-|3-x|

∣ x - 2 ∣ > 2 + x - ∣ 3 - x ∣

|x-1|+|x-2|+|x-3|<= 6

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ \leq 6

1/(|x-2|)>= 1/4

\frac{1}{∣ x - 2 ∣} \geq \frac{1}{4}

\frac{5}{( 3 - x )} > 1

4|x-2|-2-x<4x+1

4 ∣ x - 2 ∣ - 2 - x < 4 x + 1

Frequently Asked Questions (FAQ)

What is |-x^2-9x-7|>= 1 ?
The solution to |-x^2-9x-7|>= 1 is x<= (-sqrt(57)-9)/2 \lor-8<= x<=-1\lor x>= (sqrt(57)-9)/2