What is (3|x|-2)/(|x|-1)>= 2 ?

The solution to (3|x|-2)/(|x|-1)>= 2 is x 1

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(3|x|-2)/(|x|-1)>= 2

\frac{3 ∣ x ∣ - 2}{∣ x ∣ - 1} \geq 2

x < - 1 or x = 0 or x > 1

Solution steps

\frac{3 ∣ x ∣ - 2}{∣ x ∣ - 1} \geq 2

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x < - 1 or No Solution or x = 0 or x > 1

Merge Overlapping Intervals

x < - 1 or x = 0 or x > 1

x ∣ x + 1 ∣ + ∣ x ∣ > 3

∣ 3 - 5 x ∣ \leq 10

\frac{( 2 - ∣ x ∣ )}{∣ 2 + x ∣} \leq \frac{3}{( ∣ x ∣ - 1 )}

x^{2} - 3 x + 2 + 2 x - 1 < 0

∣ 3 x + 3 ∣ \leq 2 x + 2

What is (3|x|-2)/(|x|-1)>= 2 ?
The solution to (3|x|-2)/(|x|-1)>= 2 is x<-1\lor x=0\lor x>1