What is x+|3-2x|>|x+1|-1 ?

The solution to x+|3-2x|>|x+1|-1 is x 3/2

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x+|3-2x|>|x+1|-1

x + ∣ 3 - 2 x ∣ > ∣ x + 1 ∣ - 1

x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Decimal Notation

x < 1.5 or x > 1.5

Solution steps

x + ∣ 3 - 2 x ∣ > ∣ x + 1 ∣ - 1

Find positive and negative intervals

x < - 1, - 1 \leq x \leq \frac{3}{2}, x > \frac{3}{2}

Solve the inequality for each interval

x < - 1 or - 1 \leq x < \frac{3}{2} or x > \frac{3}{2}

Merge Overlapping Intervals

x < \frac{3}{2} or x > \frac{3}{2}

∣ x - 1 ∣^{x^{4} - 4 x^{3} + 3 x^{2}} < 1

∣ 15 - x ∣ > 25

∣ 2 x - 1 ∣ < ∣ x + 1 ∣

7 x^{2} - 7 x + 12 < ∣ x - 4 ∣

\frac{( x - 1 )}{( 2 - x )} > 0

What is x+|3-2x|>|x+1|-1 ?
The solution to x+|3-2x|>|x+1|-1 is x< 3/2 \lor x> 3/2