What is 2<|x-1|+|x-3| ?

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2<|x-1|+|x-3|

2 < ∣ x - 1 ∣ + ∣ x - 3 ∣

x < 1 or x > 3

Solution steps

2 < ∣ x - 1 ∣ + ∣ x - 3 ∣

Find positive and negative intervals

x < 1, 1 \leq x < 3, x \geq 3

Solve the inequality for each interval

x < 1 or No Solution or x > 3

Merge Overlapping Intervals

x < 1 or x > 3

lo g_{x^{2}} (\frac{( 4 x - 5 )}{∣ x - 2 ∣}) \geq \frac{1}{2}

∣ 2 x - 2 ∣ \leq 6

∣ 3 x ∣ > 1

∣ 5 - (m - 3) ∣ + 8 < 15

∣ 4 x - 3 ∣ < 10