What is |((x-4))/((x^2-36))|<= 0 ?

The solution to |((x-4))/((x^2-36))|<= 0 is x=4

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|((x-4))/((x^2-36))|<= 0

\frac{( x - 4 )}{( x ^{2} - 36 )} \leq 0

x = 4

Interval Notation

x = 4

Solution steps

\frac{x - 4}{x ^{2} - 36} \leq 0

Apply absolute rule: If

∣ u ∣ \leq 0

then

u = 0

\frac{x - 4}{x ^{2} - 36} = 0

\frac{x - 4}{x ^{2} - 36} = 0 : x = 4

Verify Solutions:

x = 4

The solution is

x = 4

3 ∣ x - 3 ∣ + ∣ x + 4 ∣ \geq 12

x^{2} - 5 x + 4 - x^{2} - 4 < 0

∣ x + 2 ∣ < 4 ∣ 2 x - 3 ∣

x^{2} - ∣ x + 2 ∣ + x => 0

∣ 4 - x ∣ < - 11

What is |((x-4))/((x^2-36))|<= 0 ?
The solution to |((x-4))/((x^2-36))|<= 0 is x=4