What is |((x-2)}{(x-2)}|*(\frac{-1)/2)<= 0 ?

The solution to |((x-2)}{(x-2)}|*(\frac{-1)/2) 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|((x-2)}{(x-2)}|*(\frac{-1)/2)<= 0

\frac{( x - 2 )}{( x - 2 )} \cdot (\frac{- 1}{2}) \leq 0

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

\frac{x - 2}{x - 2} \frac{- 1}{2} \leq 0

Multiply both sides by

- 1

\frac{1}{2} \frac{x - 2}{x - 2} \geq 0

Multiply both sides by

2

\frac{x - 2}{x - 2} \geq 0

Absolute values are always greater or equal to 0

True for all x

Verify Solutions:

x < 2 or x > 2

The solution is

x < 2 or x > 2

x^{2} - 4 \leq 0

(∣ x ∣ - 5) (∣ x ∣ - 7) \leq 0

(c) ∣ x - 3 ∣ - ∣ x + 2 ∣ \leq 3

x^{2} + x + x - 1 < 0

∣ u - 6 ∣ < 5

What is |((x-2)}{(x-2)}|*(\frac{-1)/2)<= 0 ?
The solution to |((x-2)}{(x-2)}|*(\frac{-1)/2)<= 0 is x<2\lor x>2