What is |x+2-x^2|<= |x^2-3x+4| ?

The solution to |x+2-x^2|<= |x^2-3x+4| is x<= 3

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|x+2-x^2|<= |x^2-3x+4|

x + 2 - x^{2} \leq x^{2} - 3 x + 4

x \leq 3

Interval Notation

(- \infty, 3]

Solution steps

x + 2 - x^{2} \leq x^{2} - 3 x + 4

Find positive and negative intervals

x < - 1, - 1 \leq x \leq 2, x > 2

Solve the inequality for each interval

x < - 1 or - 1 \leq x \leq 2 or 2 < x \leq 3

Merge Overlapping Intervals

x \leq 3

(\frac{( ∣ x + 1 ∣ + 5 )}{∣ 2 - x ∣}) > 5

∣ 2 x + 4.5 ∣ > ∣ x - 2.7 ∣

x, f > - ∣ x - 2 ∣ + 4

(a) ∣ x - 2 ∣ \leq ∣ x + 4 ∣

\frac{2}{x + 3} \leq 1

What is |x+2-x^2|<= |x^2-3x+4| ?
The solution to |x+2-x^2|<= |x^2-3x+4| is x<= 3