What are the solutions to the equation 8x^2+x+2=0 ?

The solutions to the equation 8x^2+x+2=0 are x=-1/16+i(3sqrt(7))/(16),x=-1/16-i(3sqrt(7))/(16)

Find the zeros of 8x^2+x+2=0

The zeros of 8x^2+x+2=0 are x=-1/16+i(3sqrt(7))/(16),x=-1/16-i(3sqrt(7))/(16)

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8 x^{2} + x + 2 = 0

x = - \frac{1}{16} + i \frac{3 7}{16}, x = - \frac{1}{16} - i \frac{3 7}{16}

Solution steps

8 x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

Simplify

1^{2} - 4 \cdot 8 \cdot 2 : 37 i

x_{1, 2} = \frac{- 1 \pm 3 7 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 1 + 3 7 i}{2 \cdot 8}, x_{2} = \frac{- 1 - 3 7 i}{2 \cdot 8}

x = \frac{- 1 + 3 7 i}{2 \cdot 8} : - \frac{1}{16} + i \frac{3 7}{16}

x = \frac{- 1 - 3 7 i}{2 \cdot 8} : - \frac{1}{16} - i \frac{3 7}{16}

The solutions to the quadratic equation are:

x = - \frac{1}{16} + i \frac{3 7}{16}, x = - \frac{1}{16} - i \frac{3 7}{16}

\frac{1}{4} (3)

x 2 = 2

5 x^{3} - 2 x^{2} + 20 x - 8

(\frac{12 a ^{3} b ^{5}}{4 a ^{6} b ^{3}})^{3}

18 < 4 x + 2 < 24

What are the solutions to the equation 8x^2+x+2=0 ?
The solutions to the equation 8x^2+x+2=0 are x=-1/16+i(3sqrt(7))/(16),x=-1/16-i(3sqrt(7))/(16)
Find the zeros of 8x^2+x+2=0
The zeros of 8x^2+x+2=0 are x=-1/16+i(3sqrt(7))/(16),x=-1/16-i(3sqrt(7))/(16)