What is 2x-1>= x+((7-x))/3 >2 ?

The solution to 2x-1>= x+((7-x))/3 >2 is x>= 5/2

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2x-1>= x+((7-x))/3 >2

2 x - 1 \geq x + \frac{( 7 - x )}{3} > 2

x \geq \frac{5}{2}

Interval Notation

[\frac{5}{2}, \infty)

Decimal Notation

x \geq 2.5

Solution steps

2 x - 1 \geq x + \frac{( 7 - x )}{3} > 2

a \geq u > b

then

a \geq u and u > b

2 x - 1 \geq x + \frac{( 7 - x )}{3} and x + \frac{( 7 - x )}{3} > 2

2 x - 1 \geq x + \frac{7 - x}{3} : x \geq \frac{5}{2}

x + \frac{7 - x}{3} > 2 : x > - \frac{1}{2}

Combine the intervals

x \geq \frac{5}{2} and x > - \frac{1}{2}

Merge Overlapping Intervals

x \geq \frac{5}{2}

8 < x < 10, x < 5

- 5 \leq \frac{( 2 - 3 x )}{4} \leq 9

2 < ∣ 2 x - 6 ∣ < 6

0 < t < 4

3 x - 5 < 26 < 4 x - 6

What is 2x-1>= x+((7-x))/3 >2 ?
The solution to 2x-1>= x+((7-x))/3 >2 is x>= 5/2