What are the solutions to the equation x^2+484=0 ?

The solutions to the equation x^2+484=0 are x=22i,x=-22i

Find the zeros of x^2+484=0

The zeros of x^2+484=0 are x=22i,x=-22i

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x^{2} + 484 = 0

x = 22 i, x = - 22 i

Solution steps

x^{2} + 484 = 0

Move

484

to the right side

x^{2} = - 484

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 484, x = - - 484

- 484 = 22 i

- - 484 = - 22 i

x = 22 i, x = - 22 i

2. 8^{2}

\frac{0.00019}{1.25} = \frac{x}{0.75}

∣ 2 x - 5 ∣ = 10

5 u^{2} - 7 u - 6 = 0

2 a^{2} pq + 2 ab p g - 112 b^{2} pq

What are the solutions to the equation x^2+484=0 ?
The solutions to the equation x^2+484=0 are x=22i,x=-22i
Find the zeros of x^2+484=0
The zeros of x^2+484=0 are x=22i,x=-22i