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Popular >

-7<3x+2<= 5

Solution

- 7 < 3 x + 2 \leq 5

Solution

- 3 < x \leq 1

+1

Interval Notation

(- 3, 1]

Solution steps

- 7 < 3 x + 2 \leq 5

If

a < u \leq b

then

a < u and u \leq b

- 7 < 3 x + 2 and 3 x + 2 \leq 5

- 7 < 3 x + 2 : x > - 3

3 x + 2 \leq 5 : x \leq 1

Combine the intervals

x > - 3 and x \leq 1

Merge Overlapping Intervals

- 3 < x \leq 1

Popular Examples

- 3 < 2 + 4 x < 12

((2^{1-x}-2^x+1))/((2^x-1))<= 0

\frac{( 2 ^{1 - x} - 2 ^{x} + 1 )}{( 2 ^{x} - 1 )} \leq 0

2^x+2^{-x+1}-3<0

2^{x} + 2^{- x + 1} - 3 < 0

(3/2)^{1+x^2}>(2/3)^{3x-1}

(\frac{3}{2})^{1 + x^{2}} > (\frac{2}{3})^{3 x - 1}

((2^{x-1}-1))/((2^{x+1)+1)}<2

\frac{( 2 ^{x - 1} - 1 )}{( 2 ^{x + 1} + 1 )} < 2

Frequently Asked Questions (FAQ)

What is -7<3x+2<= 5 ?
The solution to -7<3x+2<= 5 is -3<x<= 1