What are the solutions to the equation 2x^1+3x^2=2 ?

The solutions to the equation 2x^1+3x^2=2 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3

Find the zeros of 2x^1+3x^2=2

The zeros of 2x^1+3x^2=2 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3

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2 x^{1} + 3 x^{2} = 2

x = \frac{- 1 + 7}{3}, x = - \frac{1 + 7}{3}

Decimal Notation

x = 0.54858 \dots, x = - 1.21525 \dots

Solution steps

2 x^{1} + 3 x^{2} = 2

Refine

2 x + 3 x^{2} = 2

Move

2

to the left side

2 x + 3 x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 2) = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 7}{2 \cdot 3}

x = \frac{- 2 + 2 7}{2 \cdot 3} : \frac{- 1 + 7}{3}

x = \frac{- 2 - 2 7}{2 \cdot 3} : - \frac{1 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{3}, x = - \frac{1 + 7}{3}

x^{4} - 11 x^{2} + 18

\frac{- 2}{- 3}

- \frac{11}{2} (\frac{1}{100}) + \frac{11}{2}

\frac{5}{6} x - \frac{1}{5} x + 4 = \frac{7}{10} x

72 g^{2} h - 43 g h + 6 h

What are the solutions to the equation 2x^1+3x^2=2 ?
The solutions to the equation 2x^1+3x^2=2 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3
Find the zeros of 2x^1+3x^2=2
The zeros of 2x^1+3x^2=2 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3