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Popular >

solvefor x,f>4^x-2

Solution

solve for

x, f > 4^{x} - 2

Solution

x < lo g_{4} (f + 2)

Solution steps

f > 4^{x} - 2

Switch sides

4^{x} - 2 < f

Move

2

to the right side

4^{x} < f + 2

Apply exponent rules

x < lo g_{4} (f + 2)

Verify Solutions:

x < lo g_{4} (f + 2)

The solution is

x < lo g_{4} (f + 2)

Popular Examples

(0.2)^{((2x-1))/((1-x))}>5

(0.2)^{\frac{( 2 x - 1 )}{( 1 - x )}} > 5

4^{x} < 2^{x + 1} + 3

3^{x} + 3^{2 - x} > 10

([2^{1-x}-2^x+1])/([2^x-1])<0

\frac{[ 2 ^{1 - x} - 2 ^{x} + 1 ]}{[ 2 ^{x} - 1 ]} < 0

e^{x - 1} > 0

Frequently Asked Questions (FAQ)

What is solvefor x,f>4^x-2 ?
The solution to solvefor x,f>4^x-2 is x<log_{4}(f+2)