What is log_{10}(x-2)(3x^2-x-1)>0 ?

The solution to log_{10}(x-2)(3x^2-x-1)>0 is x>3

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log_{10}(x-2)(3x^2-x-1)>0

lo g_{10} (x - 2) (3 x^{2} - x - 1) > 0

x > 3

Interval Notation

(3, \infty)

Solution steps

lo g_{10} (x - 2) (3 x^{2} - x - 1) > 0

Identify the intervals

x > 3

2 - lo g_{10} (4 x) \geq 0

lo g_{2} (x - 1) > - 1

lo g_{x - 2} (3 x^{2} - x - 1) > 0

lo g_{4} (x^{2} + 2 x) > lo g_{2} (x - 4)

lo g_{\frac{1}{4}} (2 - x) > lo g_{\frac{1}{4}} (\frac{2}{( x + 1 )})

What is log_{10}(x-2)(3x^2-x-1)>0 ?
The solution to log_{10}(x-2)(3x^2-x-1)>0 is x>3