What is log_{3x+5}(9x^2+8x+8)>2 ?

The solution to log_{3x+5}(9x^2+8x+8)>2 is -4/3 <x<-17/22

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log_{3x+5}(9x^2+8x+8)>2

lo g_{3 x + 5} (9 x^{2} + 8 x + 8) > 2

- \frac{4}{3} < x < - \frac{17}{22}

Interval Notation

(- \frac{4}{3}, - \frac{17}{22})

Decimal Notation

- 1.33333 \dots < x < - 0.77272 \dots

Solution steps

lo g_{3 x + 5} (9 x^{2} + 8 x + 8) > 2

Apply log rules

- \frac{4}{3} < x < - \frac{17}{22}

lo g_{2} (x - 1) + lo g_{2} (x) > 1

\frac{1}{2 lo g _{10} ( n ^{2} - 1 )} > 1

lo g_{\frac{1}{3}} (3 x + 4) > lo g_{\frac{1}{3}} (x^{2} + 2)

lo g_{- 6 x - 5 x^{2}} (6^{x}) > 0

ln (x + 1) < x

What is log_{3x+5}(9x^2+8x+8)>2 ?
The solution to log_{3x+5}(9x^2+8x+8)>2 is -4/3 <x<-17/22