What is log_{7}(((2x-6))/((2x-1)))>0 ?

The solution to log_{7}(((2x-6))/((2x-1)))>0 is x< 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{7}(((2x-6))/((2x-1)))>0

lo g_{7} (\frac{( 2 x - 6 )}{( 2 x - 1 )}) > 0

x < \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2})

Decimal Notation

x < 0.5

Solution steps

lo g_{7} (\frac{2 x - 6}{2 x - 1}) > 0

Apply log rules

\frac{2 x - 6}{2 x - 1} > 1

\frac{2 x - 6}{2 x - 1} > 1 : x < \frac{1}{2}

x < \frac{1}{2}

(lo g_{0.5} (x))^{2} + lo g_{0.5} (x) - 2 \leq 0

2 - lo g_{10} (4 x) > 0

lo g_{x}^{2} (2 + x) < 1

\frac{1}{2 ^{l o g_{10} (x^{2} - 1)}} > 1

lo g_{3} (x^{2} - 16) < 2

What is log_{7}(((2x-6))/((2x-1)))>0 ?
The solution to log_{7}(((2x-6))/((2x-1)))>0 is x< 1/2