What is log_{10}(((x^2-36))/((48+22x-5x^2)))>= 0 ?

The solution to log_{10}(((x^2-36))/((48+22x-5x^2)))>= 0 is -7/3 <= x<-8/5

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log_{10}(((x^2-36))/((48+22x-5x^2)))>= 0

lo g_{10} (\frac{( x ^{2} - 36 )}{( 48 + 22 x - 5 x ^{2} )}) \geq 0

- \frac{7}{3} \leq x < - \frac{8}{5}

Interval Notation

[- \frac{7}{3}, - \frac{8}{5})

Decimal Notation

- 2.33333 \dots \leq x < - 1.6

Solution steps

lo g_{10} (\frac{x ^{2} - 36}{48 + 22 x - 5 x ^{2}}) \geq 0

Apply log rules

\frac{x ^{2} - 36}{48 + 22 x - 5 x ^{2}} \geq 1

\frac{x ^{2} - 36}{48 + 22 x - 5 x ^{2}} \geq 1 : - \frac{7}{3} \leq x < - \frac{8}{5}

- \frac{7}{3} \leq x < - \frac{8}{5}

lo g_{2} (\frac{( 3 x - 4 )}{( x )}) > 1

lo g_{6} (\frac{( x - 2 )}{( 6 - x )}) > 0

lo g_{3} (y) + y < 4

ln (x - 1) \geq - 1

ln (e^{x} - 1) > 0

What is log_{10}(((x^2-36))/((48+22x-5x^2)))>= 0 ?
The solution to log_{10}(((x^2-36))/((48+22x-5x^2)))>= 0 is -7/3 <= x<-8/5