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Popular >

2>= 1+ln(b)

Solution

2 \geq 1 + ln (b)

Solution

0 < b \leq e

+2

Interval Notation

(0, e]

Decimal Notation

0 < b \leq 2.71828 \dots

Solution steps

2 \geq 1 + ln (b)

Switch sides

1 + ln (b) \leq 2

Move

1

to the right side

ln (b) \leq 1

Apply log rules

b \leq e and b > 0

Merge Overlapping Intervals

0 < b \leq e

Popular Examples

log_{6}(x^2)>= log_{6}(9)

lo g_{6} (x^{2}) \geq lo g_{6} (9)

log_{1/2}(log_{2}(x/((1+x))))>0

lo g_{\frac{1}{2}} (lo g_{2} (\frac{x}{( 1 + x )})) > 0

log_{x}((2x-3)/4)>2

lo g_{x} (\frac{2 x - 3}{4}) > 2

lo g_{4} (- x) < 0

log_{1/4}(((35-x^2))/x)>= (-1)/2

lo g_{\frac{1}{4}} (\frac{( 35 - x ^{2} )}{x}) \geq \frac{- 1}{2}

Frequently Asked Questions (FAQ)

What is 2>= 1+ln(b) ?
The solution to 2>= 1+ln(b) is 0<b<= e