What is sqrt(x-2)>=-1 ?

The solution to sqrt(x-2)>=-1 is x>= 2

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sqrt(x-2)>=-1

x - 2 \geq - 1

x \geq 2

Interval Notation

[2, \infty)

Solution steps

x - 2 \geq - 1

If n is even,

for all

u

True for all x

Find singularity points

Find non-negative values for radicals:

x \geq 2

Combine the intervals

True for all x and x \geq 2

Merge Overlapping Intervals

x \geq 2

x - 1 - x < 0

x^{2} + x - 12 < x

5 - 2 x < 6 x - 1

6 x - x^{2} < 3 + x

\frac{- 3}{( x ^{2} + 2 x + 10 )} \geq 0