What is ((1-sqrt(21-4x-x^2)))/((x+1))>= 0 ?

The solution to ((1-sqrt(21-4x-x^2)))/((x+1))>= 0 is -2(1+sqrt(6))<= x<-1\lor 2(sqrt(6)-1)<= x<= 3

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((1-sqrt(21-4x-x^2)))/((x+1))>= 0

\frac{( 1 - 21 - 4 x - x ^{2} )}{( x + 1 )} \geq 0

- 2 (1 + 6) \leq x < - 1 or 2 (6 - 1) \leq x \leq 3

Interval Notation

[- 2 (1 + 6), - 1) \cup [2 (6 - 1), 3]

Decimal Notation

- 6.89897 \dots \leq x < - 1 or 2.89897 \dots \leq x \leq 3

Solution steps

\frac{1 - 21 - 4 x - x ^{2}}{x + 1} \geq 0

Identify the intervals

- 2 (1 + 6) \leq x < - 1 or 2 (6 - 1) \leq x \leq 3

x - 1 - ∣ x ∣ \leq 0

3 - x \leq 1 - x

x + 3 + x + 2 - 2 x + 4 > 0

lo g_{x} (x) < 2

x - 1 > 3 - x

What is ((1-sqrt(21-4x-x^2)))/((x+1))>= 0 ?
The solution to ((1-sqrt(21-4x-x^2)))/((x+1))>= 0 is -2(1+sqrt(6))<= x<-1\lor 2(sqrt(6)-1)<= x<= 3