What is lcm 21/2*a-1/4*b+2,(a-2b-3c)^2 ?

The solution to lcm 21/2*a-1/4*b+2,(a-2b-3c)^2 is

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lcm 21/2a-1/4b+2,(a-2b-3c)^2

lcm

\frac{21}{2} \cdot a - \frac{1}{4} \cdot b + 2, (a - 2 b - 3 c)^{2}

\frac{21}{2} a^{3} - \frac{169}{4} a^{2} b - 63 a^{2} c + 2 a^{2} + 43 a b^{2} - 8 ab + \frac{189}{2} a c^{2} + \frac{255}{2} ab c - 12 a c - b^{3} + 8 b^{2} - \frac{9}{4} b c^{2} + 18 c^{2} - 3 b^{2} c + 24 b c

Solution steps

Find Least Common Multiplier of

\frac{21}{2} \cdot a - \frac{1}{4} \cdot b + 2, (a - 2 b - 3 c)^{2}

Multiply each factor with the highest power:

(\frac{21}{2} a - \frac{1}{4} b + 2) \cdot (a - 2 b - 3 c)^{2}

Simplify

\frac{21}{2} a^{3} - \frac{169}{4} a^{2} b - 63 a^{2} c + 2 a^{2} + 43 a b^{2} - 8 ab + \frac{189}{2} a c^{2} + \frac{255}{2} ab c - 12 a c - b^{3} + 8 b^{2} - \frac{9}{4} b c^{2} + 18 c^{2} - 3 b^{2} c + 24 b c

9 \frac{x}{( 1 - x ^{2} )}, \frac{1}{( x + 1 + x ^{2} )}, \frac{1}{( x + 1 + x )}

(13 - 12 p), (13 + 12 p)

x^{2} \cdot y, - 2 x^{2} \cdot y, - 7 x^{2} \cdot y, 8 x^{2} \cdot y

- y + 6, 2 a \cdot b^{2} - 9 a

\frac{3}{( x - 1 )}, \frac{k}{( x ( x + 4 ) )}

What is lcm 21/2*a-1/4*b+2,(a-2b-3c)^2 ?
The solution to lcm 21/2*a-1/4*b+2,(a-2b-3c)^2 is