What is longdivision ((3x^3-2x^2+7x-5))/((x+3)) ?

The solution to longdivision ((3x^3-2x^2+7x-5))/((x+3)) is 3x^2-11x+40-(125)/(x+3)

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longdivision ((3x^3-2x^2+7x-5))/((x+3))

long division

\frac{( 3 x ^{3} - 2 x ^{2} + 7 x - 5 )}{( x + 3 )}

3 x^{2} - 11 x + 40 - \frac{125}{x + 3}

Solution steps

\frac{( 3 x ^{3} - 2 x ^{2} + 7 x - 5 )}{( x + 3 )}

Divide

\frac{3 x ^{3} - 2 x ^{2} + 7 x - 5}{x + 3} : \frac{3 x ^{3} - 2 x ^{2} + 7 x - 5}{x + 3} = 3 x^{2} + \frac{- 11 x ^{2} + 7 x - 5}{x + 3}

= 3 x^{2} + \frac{- 11 x ^{2} + 7 x - 5}{x + 3}

Divide

\frac{- 11 x ^{2} + 7 x - 5}{x + 3} : \frac{- 11 x ^{2} + 7 x - 5}{x + 3} = - 11 x + \frac{40 x - 5}{x + 3}

= 3 x^{2} - 11 x + \frac{40 x - 5}{x + 3}

Divide

\frac{40 x - 5}{x + 3} : \frac{40 x - 5}{x + 3} = 40 + \frac{- 125}{x + 3}

= 3 x^{2} - 11 x + 40 + \frac{- 125}{x + 3}

Simplify

= 3 x^{2} - 11 x + 40 - \frac{125}{x + 3}

\frac{( n + 1 )}{( n - 1 )}

\frac{x ^{2} - 1}{x ^{2} + 1}

\frac{( 3 a ^{3} - 16 )}{( a - 2 )}

\frac{2 x ^{2} + 5 x - 18}{x + 4}

\frac{( 2 x ^{3} - 3 x ^{2} - x + 2 )}{( x - 2 )}

What is longdivision ((3x^3-2x^2+7x-5))/((x+3)) ?
The solution to longdivision ((3x^3-2x^2+7x-5))/((x+3)) is 3x^2-11x+40-(125)/(x+3)