What is longdivision ((n+2))/((n+1)) ?

The solution to longdivision ((n+2))/((n+1)) is 1+1/(n+1)

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longdivision ((n+2))/((n+1))

long division

\frac{( n + 2 )}{( n + 1 )}

1 + \frac{1}{n + 1}

Solution steps

\frac{( n + 2 )}{( n + 1 )}

Divide

\frac{n + 2}{n + 1} : \frac{n + 2}{n + 1} = 1 + \frac{1}{n + 1}

= 1 + \frac{1}{n + 1}

\frac{( a + 2 )}{( a - 2 )}

\frac{( 2 x ^{2} + 4 x + 3 )}{( 4 x + 2 )}

\frac{( 2 x + 3 )}{( x + 1 )}

\frac{( 2 x ^{2} - x - 21 )}{( x ^{2} - 1 )}

\frac{2 x - 1}{2 x + 1}

What is longdivision ((n+2))/((n+1)) ?
The solution to longdivision ((n+2))/((n+1)) is 1+1/(n+1)