What is longdivision ((x^4-x^2+1))/((1-x)) ?

The solution to longdivision ((x^4-x^2+1))/((1-x)) is -x^3-x^2+1/(-x+1)

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longdivision ((x^4-x^2+1))/((1-x))

long division

\frac{( x ^{4} - x ^{2} + 1 )}{( 1 - x )}

- x^{3} - x^{2} + \frac{1}{- x + 1}

Solution steps

\frac{( x ^{4} - x ^{2} + 1 )}{( 1 - x )}

Divide

\frac{x ^{4} - x ^{2} + 1}{- x + 1} : \frac{x ^{4} - x ^{2} + 1}{- x + 1} = - x^{3} + \frac{x ^{3} - x ^{2} + 1}{- x + 1}

= - x^{3} + \frac{x ^{3} - x ^{2} + 1}{- x + 1}

Divide

\frac{x ^{3} - x ^{2} + 1}{- x + 1} : \frac{x ^{3} - x ^{2} + 1}{- x + 1} = - x^{2} + \frac{1}{- x + 1}

= - x^{3} - x^{2} + \frac{1}{- x + 1}

\frac{( 6 a ^{2} - 7 a + 5 )}{( 2 a - 3 )}

\frac{( 2 x ^{2} + 5 x - 7 )}{( x - 2 )}

\frac{( 3 x + 2 )}{( 7 x - 1 )}

\frac{( 8 x + 7 )}{( 10 x - 9 )}

\frac{( n - 2 )}{( n + 1 )}

What is longdivision ((x^4-x^2+1))/((1-x)) ?
The solution to longdivision ((x^4-x^2+1))/((1-x)) is -x^3-x^2+1/(-x+1)