What is ((2u^4)/(4uv^{-5)})^{-3} ?

The solution to ((2u^4)/(4uv^{-5)})^{-3} is 8/(u^9v^{15)}

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simplify ((2u^4)/(4uv^{-5)})^{-3}

simplify

(\frac{2 u ^{4}}{4 u v ^{- 5}})^{- 3}

\frac{8}{u ^{9} v ^{15}}

Solution steps

(\frac{2 u ^{4}}{4 u v ^{- 5}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 u ^{4}}{4 u v ^{- 5}})^{- 3} = \frac{1}{( \frac{2 u ^{4}}{4 u v ^{- 5}} ) ^{3}}

= \frac{1}{( \frac{2 u ^{4}}{4 u v ^{- 5}} ) ^{3}}

Simplify

(\frac{2 u ^{4}}{4 u v ^{- 5}})^{3} : \frac{u ^{9} v ^{15}}{8}

= \frac{1}{\frac{u ^{9} v ^{15}}{8}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{8}{u ^{9} v ^{15}}

- (5 x + 1)

- x - 2 + 15 x

- 3 (- 9 v - 4) - 2 (v - 2)

25 x^{2} y^{3} + 55 x y^{3}

8 (- 9)

What is ((2u^4)/(4uv^{-5)})^{-3} ?
The solution to ((2u^4)/(4uv^{-5)})^{-3} is 8/(u^9v^{15)}