What is (x+3)^2-4(x+3) ?

The solution to (x+3)^2-4(x+3) is x^2+2x-3

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simplify (x+3)^2-4(x+3)

simplify

(x + 3)^{2} - 4 (x + 3)

x^{2} + 2 x - 3

Solution steps

(x + 3)^{2} - 4 (x + 3)

Expand

(x + 3)^{2} : x^{2} + 6 x + 9

= x^{2} + 6 x + 9 - 4 (x + 3)

Expand

- 4 (x + 3) : - 4 x - 12

= x^{2} + 6 x + 9 - 4 x - 12

Group like terms

= x^{2} + 6 x - 4 x + 9 - 12

Add similar elements:

6 x - 4 x = 2 x

= x^{2} + 2 x + 9 - 12

Subtract the numbers:

9 - 12 = - 3

= x^{2} + 2 x - 3

- 6 + 3 a - b - 4 a + 4 b + 5

7 + 212

4 x y - 6 x y + 5 y - 9 x

sin^{3} (x) + cos^{2} (x) sin (x)

(- 5) - 6