What is (2x^2-4)-(-x^2+3x-6) ?

The solution to (2x^2-4)-(-x^2+3x-6) is 3x^2-3x+2

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simplify (2x^2-4)-(-x^2+3x-6)

simplify

(2 x^{2} - 4) - (- x^{2} + 3 x - 6)

3 x^{2} - 3 x + 2

Solution steps

(2 x^{2} - 4) - (- x^{2} + 3 x - 6)

Apply rule:

(a) = a

(2 x^{2} - 4) = 2 x^{2} - 4

= 2 x^{2} - 4 - (- x^{2} + 3 x - 6)

Apply the distributive law:

- (- a + b) = a - b

- (- x^{2} + 3 x - 6) = x^{2} - 3 x + 6

= 2 x^{2} - 4 + x^{2} - 3 x + 6

Group like terms

= 2 x^{2} + x^{2} - 3 x - 4 + 6

Add similar elements:

2 x^{2} + x^{2} = 3 x^{2}

= 3 x^{2} - 3 x - 4 + 6

Add the numbers:

- 4 + 6 = 2

= 3 x^{2} - 3 x + 2

(3 x^{2} + 10) - (- 7 x^{2} - 9 x)

9 a^{3} + a

(x + 5)^{2} - x^{2}

(a + 6) (a - 6) - a^{2}

x^{4} + 64 x

What is (2x^2-4)-(-x^2+3x-6) ?
The solution to (2x^2-4)-(-x^2+3x-6) is 3x^2-3x+2