What are the solutions to the equation x^2+22x+105=0 ?

The solutions to the equation x^2+22x+105=0 are x=-7,x=-15

Find the zeros of x^2+22x+105=0

The zeros of x^2+22x+105=0 are x=-7,x=-15

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x^{2} + 22 x + 105 = 0

x = - 7, x = - 15

Solution steps

x^{2} + 22 x + 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 105}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 105 = 8

x_{1, 2} = \frac{- 22 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 8}{2 \cdot 1}, x_{2} = \frac{- 22 - 8}{2 \cdot 1}

x = \frac{- 22 + 8}{2 \cdot 1} : - 7

x = \frac{- 22 - 8}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 7, x = - 15

x^{2} - 80 = 0

- 5 - (- 6)

(- \frac{1}{2})^{- 2}

3 x^{2} + 14 x - 40 = 0

(\frac{3}{2})^{3}

What are the solutions to the equation x^2+22x+105=0 ?
The solutions to the equation x^2+22x+105=0 are x=-7,x=-15
Find the zeros of x^2+22x+105=0
The zeros of x^2+22x+105=0 are x=-7,x=-15