What are the solutions to the equation 7x^2+21x-28=0 ?

The solutions to the equation 7x^2+21x-28=0 are x=1,x=-4

Find the zeros of 7x^2+21x-28=0

The zeros of 7x^2+21x-28=0 are x=1,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x^{2} + 21 x - 28 = 0

x = 1, x = - 4

Solution steps

7 x^{2} + 21 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 7 ( - 28 )}{2 \cdot 7}

2 1^{2} - 4 \cdot 7 (- 28) = 35

x_{1, 2} = \frac{- 21 \pm 35}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 21 + 35}{2 \cdot 7}, x_{2} = \frac{- 21 - 35}{2 \cdot 7}

x = \frac{- 21 + 35}{2 \cdot 7} : 1

x = \frac{- 21 - 35}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

4^{10}

\frac{y}{5} + 2 y - \frac{4}{3} = 2

∣ 4 x - 5 ∣ > - 99

- 8 + 8 i

3 t^{2} - 16 t + 3 = 0

What are the solutions to the equation 7x^2+21x-28=0 ?
The solutions to the equation 7x^2+21x-28=0 are x=1,x=-4
Find the zeros of 7x^2+21x-28=0
The zeros of 7x^2+21x-28=0 are x=1,x=-4