What is (2k^2-5k-3)/(k^3-27) ?

The solution to (2k^2-5k-3)/(k^3-27) is (2k+1)/(k^2+3k+9)

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simplify (2k^2-5k-3)/(k^3-27)

simplify

\frac{2 k ^{2} - 5 k - 3}{k ^{3} - 27}

\frac{2 k + 1}{k ^{2} + 3 k + 9}

Solution steps

\frac{2 k ^{2} - 5 k - 3}{k ^{3} - 27}

Factor

2 k^{2} - 5 k - 3 : (2 k + 1) (k - 3)

= \frac{( 2 k + 1 ) ( k - 3 )}{k ^{3} - 27}

Factor

k^{3} - 27 : (k - 3) (k^{2} + 3 k + 9)

= \frac{( 2 k + 1 ) ( k - 3 )}{( k - 3 ) ( k ^{2} + 3 k + 9 )}

Cancel the common factor:

k - 3

= \frac{2 k + 1}{k ^{2} + 3 k + 9}

\frac{9}{10} (- \frac{2}{3})

(x^{2} - 3 y + 1) (x^{2} + 2 x)

(5 x^{2} + 4 x + 8) - (- 9 x - 3)

7 x^{9} \cdot (- 3 x^{4})

\frac{5}{14 - 2}

What is (2k^2-5k-3)/(k^3-27) ?
The solution to (2k^2-5k-3)/(k^3-27) is (2k+1)/(k^2+3k+9)