What is (-x^2-4x+1)-(2x^2+9) ?

The solution to (-x^2-4x+1)-(2x^2+9) is -3x^2-4x-8

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simplify (-x^2-4x+1)-(2x^2+9)

simplify

(- x^{2} - 4 x + 1) - (2 x^{2} + 9)

- 3 x^{2} - 4 x - 8

Solution steps

(- x^{2} - 4 x + 1) - (2 x^{2} + 9)

Apply rule:

(a) = a

(- x^{2} - 4 x + 1) = - x^{2} - 4 x + 1

= - x^{2} - 4 x + 1 - (2 x^{2} + 9)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{2} + 9) = - 2 x^{2} - 9

= - x^{2} - 4 x + 1 - 2 x^{2} - 9

Group like terms

= - x^{2} - 2 x^{2} - 4 x + 1 - 9

Add similar elements:

- x^{2} - 2 x^{2} = - 3 x^{2}

= - 3 x^{2} - 4 x + 1 - 9

Subtract the numbers:

1 - 9 = - 8

= - 3 x^{2} - 4 x - 8

(4 x^{2} - 3 x + 8) + (3 x^{2} - 9 x + 4)

\frac{5}{6} (x + \frac{1}{2} + 4)

\frac{1}{4} \div \frac{2}{7}

2 x^{2} \cdot 6 x

(4 x^{2} - 10 x) + (2 x^{2} + 5 x - 5)

What is (-x^2-4x+1)-(2x^2+9) ?
The solution to (-x^2-4x+1)-(2x^2+9) is -3x^2-4x-8