What are the solutions to the equation 7x^2+3x=2 ?

The solutions to the equation 7x^2+3x=2 are x=(-3+sqrt(65))/(14),x=(-3-sqrt(65))/(14)

Find the zeros of 7x^2+3x=2

The zeros of 7x^2+3x=2 are x=(-3+sqrt(65))/(14),x=(-3-sqrt(65))/(14)

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7 x^{2} + 3 x = 2

x = \frac{- 3 + 65}{14}, x = \frac{- 3 - 65}{14}

Decimal Notation

x = 0.36158 \dots, x = - 0.79016 \dots

Solution steps

7 x^{2} + 3 x = 2

Move

2

to the left side

7 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 7 ( - 2 )}{2 \cdot 7}

3^{2} - 4 \cdot 7 (- 2) = 65

x_{1, 2} = \frac{- 3 \pm 65}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 3 + 65}{2 \cdot 7}, x_{2} = \frac{- 3 - 65}{2 \cdot 7}

x = \frac{- 3 + 65}{2 \cdot 7} : \frac{- 3 + 65}{14}

x = \frac{- 3 - 65}{2 \cdot 7} : \frac{- 3 - 65}{14}

The solutions to the quadratic equation are:

x = \frac{- 3 + 65}{14}, x = \frac{- 3 - 65}{14}

\frac{3}{2} = \frac{a}{69}

2 (7 y - 5) = 4

\frac{a}{6} < - 13

∣ 2 x + 7 ∣ + 7 > 6

9 x^{2} - y^{10}

What are the solutions to the equation 7x^2+3x=2 ?
The solutions to the equation 7x^2+3x=2 are x=(-3+sqrt(65))/(14),x=(-3-sqrt(65))/(14)
Find the zeros of 7x^2+3x=2
The zeros of 7x^2+3x=2 are x=(-3+sqrt(65))/(14),x=(-3-sqrt(65))/(14)