What is ((x^{-3}y^4)/5)^{-3} ?

The solution to ((x^{-3}y^4)/5)^{-3} is (125x^9)/(y^{12)}

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simplify ((x^{-3}y^4)/5)^{-3}

simplify

(\frac{x ^{- 3} y ^{4}}{5})^{- 3}

\frac{125 x ^{9}}{y ^{12}}

Solution steps

(\frac{x ^{- 3} y ^{4}}{5})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{x ^{- 3} y ^{4}}{5})^{- 3} = \frac{1}{( \frac{x ^{- 3} y ^{4}}{5} ) ^{3}}

= \frac{1}{( \frac{x ^{- 3} y ^{4}}{5} ) ^{3}}

Simplify

(\frac{x ^{- 3} y ^{4}}{5})^{3} : \frac{y ^{12}}{125 x ^{9}}

= \frac{1}{\frac{y ^{12}}{125 x ^{9}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{125 x ^{9}}{y ^{12}}

x (2 x + 3 (x - (3 x + 1)))

2 a (3 a^{5} 2 b^{4})^{3}

2 - \frac{x + 1}{x - 3}

\frac{x ^{- 3} - x}{x ^{- 2} - 1}

\frac{3 x ^{2} + x}{x}

What is ((x^{-3}y^4)/5)^{-3} ?
The solution to ((x^{-3}y^4)/5)^{-3} is (125x^9)/(y^{12)}