What is (5x^7y^{-1})^{-2} ?

The solution to (5x^7y^{-1})^{-2} is (y^2)/(25x^{14)}

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simplify (5x^7y^{-1})^{-2}

simplify

(5 x^{7} y^{- 1})^{- 2}

\frac{y ^{2}}{25 x ^{14}}

Solution steps

(5 x^{7} y^{- 1})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(5 x^{7} y^{- 1})^{- 2} = \frac{1}{( 5 x ^{7} y ^{- 1} ) ^{2}}

= \frac{1}{( 5 x ^{7} y ^{- 1} ) ^{2}}

Simplify

(5 x^{7} y^{- 1})^{2} : \frac{25 x ^{14}}{y ^{2}}

= \frac{1}{\frac{25 x ^{14}}{y ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{2}}{25 x ^{14}}

\frac{15}{7 - 2}

\frac{1}{2} (2 a + 4 b - 4 c)

\frac{5 - x}{x ^{2} - 25}

- 3 (x - 10) + x

9 \cdot 1 0^{- 6}

What is (5x^7y^{-1})^{-2} ?
The solution to (5x^7y^{-1})^{-2} is (y^2)/(25x^{14)}