What is expand (n+4)^2(3n^2-7n+1) ?

The solution to expand (n+4)^2(3n^2-7n+1) is 3n^4+17n^3-7n^2-104n+16

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expand (n+4)^2(3n^2-7n+1)

expand

(n + 4)^{2} (3 n^{2} - 7 n + 1)

3 n^{4} + 17 n^{3} - 7 n^{2} - 104 n + 16

Solution steps

(n + 4)^{2} (3 n^{2} - 7 n + 1)

Expand

(n + 4)^{2} : n^{2} + 8 n + 16

= (n^{2} + 8 n + 16) (3 n^{2} - 7 n + 1)

Distribute parentheses

= n^{2} \cdot 3 n^{2} + n^{2} (- 7 n) + n^{2} \cdot 1 + 8 n \cdot 3 n^{2} + 8 n (- 7 n) + 8 n \cdot 1 + 16 \cdot 3 n^{2} + 16 (- 7 n) + 16 \cdot 1

Simplify

n^{2} \cdot 3 n^{2} + n^{2} (- 7 n) + n^{2} \cdot 1 + 8 n \cdot 3 n^{2} + 8 n (- 7 n) + 8 n \cdot 1 + 16 \cdot 3 n^{2} + 16 (- 7 n) + 16 \cdot 1 : 3 n^{4} + 17 n^{3} - 7 n^{2} - 104 n + 16

= 3 n^{4} + 17 n^{3} - 7 n^{2} - 104 n + 16

10 p - 4 (8 p - 2)

14 f^{3} + 42 f^{5} - 77 f^{7}

\frac{- 3.7 - 13.9}{21.4 - 7.2}

(4 x + 2) (2 x - 3)

3 (5) (- 3) (- 2)

What is expand (n+4)^2(3n^2-7n+1) ?
The solution to expand (n+4)^2(3n^2-7n+1) is 3n^4+17n^3-7n^2-104n+16