What is (x^3-9x)/(x^2-7x+12) ?

The solution to (x^3-9x)/(x^2-7x+12) is (x(x+3))/(x-4)

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simplify (x^3-9x)/(x^2-7x+12)

simplify

\frac{x ^{3} - 9 x}{x ^{2} - 7 x + 12}

\frac{x ( x + 3 )}{x - 4}

Solution steps

\frac{x ^{3} - 9 x}{x ^{2} - 7 x + 12}

Factor

x^{3} - 9 x : x (x + 3) (x - 3)

= \frac{x ( x + 3 ) ( x - 3 )}{x ^{2} - 7 x + 12}

Factor

x^{2} - 7 x + 12 : (x - 3) (x - 4)

= \frac{x ( x + 3 ) ( x - 3 )}{( x - 3 ) ( x - 4 )}

Cancel the common factor:

x - 3

= \frac{x ( x + 3 )}{x - 4}

10 x \cdot 8 x

50 x - 8 x

20 u^{2} x^{2} y + 8 u^{2} y + 24 u^{2}

(6 a - 7 b^{2}) (- 3 a + 9 b^{2})

[(x^{2} y^{- 2})^{- 1}]^{- 1}

What is (x^3-9x)/(x^2-7x+12) ?
The solution to (x^3-9x)/(x^2-7x+12) is (x(x+3))/(x-4)