What are the solutions to the equation x^2+81x+18=54 ?

The solutions to the equation x^2+81x+18=54 are x=(-81+3sqrt(745))/2 ,x=(-81-3sqrt(745))/2

Find the zeros of x^2+81x+18=54

The zeros of x^2+81x+18=54 are x=(-81+3sqrt(745))/2 ,x=(-81-3sqrt(745))/2

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x^{2} + 81 x + 18 = 54

x = \frac{- 81 + 3 745}{2}, x = \frac{- 81 - 3 745}{2}

Decimal Notation

x = 0.44203 \dots, x = - 81.44203 \dots

Solution steps

x^{2} + 81 x + 18 = 54

Move

54

to the left side

x^{2} + 81 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 81 \pm 8 1 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

8 1^{2} - 4 \cdot 1 \cdot (- 36) = 3745

x_{1, 2} = \frac{- 81 \pm 3 745}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 81 + 3 745}{2 \cdot 1}, x_{2} = \frac{- 81 - 3 745}{2 \cdot 1}

x = \frac{- 81 + 3 745}{2 \cdot 1} : \frac{- 81 + 3 745}{2}

x = \frac{- 81 - 3 745}{2 \cdot 1} : \frac{- 81 - 3 745}{2}

The solutions to the quadratic equation are:

x = \frac{- 81 + 3 745}{2}, x = \frac{- 81 - 3 745}{2}

\frac{3}{2} + \frac{2}{5}

3 v + 9 - 8 v = - 31

v^{2} = 9

16 - 2 x \leq 2 x + 24

6 - 4 x \leq - 13

What are the solutions to the equation x^2+81x+18=54 ?
The solutions to the equation x^2+81x+18=54 are x=(-81+3sqrt(745))/2 ,x=(-81-3sqrt(745))/2
Find the zeros of x^2+81x+18=54
The zeros of x^2+81x+18=54 are x=(-81+3sqrt(745))/2 ,x=(-81-3sqrt(745))/2