What is expand (2x-5)(x^2-x+1) ?

The solution to expand (2x-5)(x^2-x+1) is 2x^3-7x^2+7x-5

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expand (2x-5)(x^2-x+1)

expand

(2 x - 5) (x^{2} - x + 1)

2 x^{3} - 7 x^{2} + 7 x - 5

Solution steps

(2 x - 5) (x^{2} - x + 1)

Distribute parentheses

= 2 x x^{2} + 2 x (- x) + 2 x \cdot 1 - 5 x^{2} - 5 (- x) - 5 \cdot 1

Simplify

2 x x^{2} + 2 x (- x) + 2 x \cdot 1 - 5 x^{2} - 5 (- x) - 5 \cdot 1 : 2 x^{3} - 7 x^{2} + 7 x - 5

= 2 x^{3} - 7 x^{2} + 7 x - 5

10 + (- 4)

- 2 (- 10 v + 1) - 6 v

(2 x^{2})^{- 2}

(ab c^{4}) (a^{3} b^{2} c^{4})^{2}

- \frac{1}{2} + (- \frac{1}{5})

What is expand (2x-5)(x^2-x+1) ?
The solution to expand (2x-5)(x^2-x+1) is 2x^3-7x^2+7x-5