What is 3(a+1)^2-(a+1)+2 ?

The solution to 3(a+1)^2-(a+1)+2 is 3a^2+5a+4

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simplify 3(a+1)^2-(a+1)+2

simplify

3 (a + 1)^{2} - (a + 1) + 2

3 a^{2} + 5 a + 4

Solution steps

3 (a + 1)^{2} - (a + 1) + 2

Apply the distributive law:

- (a + b) = - a - b

- (a + 1) = - a - 1

= 3 (a + 1)^{2} - a - 1 + 2

Expand

3 (a + 1)^{2} : 3 a^{2} + 6 a + 3

= 3 a^{2} + 6 a + 3 - a - 1 + 2

Group like terms

= 3 a^{2} + 6 a - a + 3 - 1 + 2

Add similar elements:

6 a - a = 5 a

= 3 a^{2} + 5 a + 3 - 1 + 2

Add the numbers:

3 - 1 + 2 = 4

= 3 a^{2} + 5 a + 4

\frac{3}{3 + 7}

v^{2} + 5 v - 36

- 2 \div \frac{2}{3}

7 (f + 4) + 2 (3 f - 8)

(4 x - 2) (2 x - 3)