What is (-2x^3y^{-4}z)^{-2} ?

The solution to (-2x^3y^{-4}z)^{-2} is (y^8)/(4x^6z^2)

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simplify (-2x^3y^{-4}z)^{-2}

simplify

(- 2 x^{3} y^{- 4} z)^{- 2}

\frac{y ^{8}}{4 x ^{6} z ^{2}}

Solution steps

(- 2 x^{3} y^{- 4} z)^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(- 2 x^{3} y^{- 4} z)^{- 2} = \frac{1}{( - 2 x ^{3} y ^{- 4} z ) ^{2}}

= \frac{1}{( - 2 x ^{3} y ^{- 4} z ) ^{2}}

Simplify

(- 2 x^{3} y^{- 4} z)^{2} : \frac{4 x ^{6} z ^{2}}{y ^{8}}

= \frac{1}{\frac{4 x ^{6} z ^{2}}{y ^{8}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{8}}{4 x ^{6} z ^{2}}

\frac{- 4 + 6}{2}

\frac{( 6 y ^{3} ) ^{4}}{2 y ^{9}}

\frac{x - 1}{2} + \frac{x}{3}

(1 - cos (x)) 1 - 1 (1 + cos (x))

m (x - y) + 2 n (x - y)

What is (-2x^3y^{-4}z)^{-2} ?
The solution to (-2x^3y^{-4}z)^{-2} is (y^8)/(4x^6z^2)