What is expand (x+1)(2x^2-2)(x^3+5) ?

The solution to expand (x+1)(2x^2-2)(x^3+5) is 2x^6+2x^5-2x^4+8x^3+10x^2-10x-10

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expand (x+1)(2x^2-2)(x^3+5)

expand

(x + 1) (2 x^{2} - 2) (x^{3} + 5)

2 x^{6} + 2 x^{5} - 2 x^{4} + 8 x^{3} + 10 x^{2} - 10 x - 10

Solution steps

(x + 1) (2 x^{2} - 2) (x^{3} + 5)

Expand

(x + 1) (2 x^{2} - 2) (x^{3} + 5) : (2 x^{3} - 2 x + 2 x^{2} - 2) (x^{3} + 5)

= (2 x^{3} - 2 x + 2 x^{2} - 2) (x^{3} + 5)

Distribute parentheses

= 2 x^{3} x^{3} + 2 x^{3} \cdot 5 - 2 x x^{3} - 2 x \cdot 5 + 2 x^{2} x^{3} + 2 x^{2} \cdot 5 - 2 x^{3} - 2 \cdot 5

Simplify

2 x^{3} x^{3} + 2 x^{3} \cdot 5 - 2 x x^{3} - 2 x \cdot 5 + 2 x^{2} x^{3} + 2 x^{2} \cdot 5 - 2 x^{3} - 2 \cdot 5 : 2 x^{6} + 2 x^{5} - 2 x^{4} + 8 x^{3} + 10 x^{2} - 10 x - 10

= 2 x^{6} + 2 x^{5} - 2 x^{4} + 8 x^{3} + 10 x^{2} - 10 x - 10

9 (2 k - 4) - 2 (7 k - 12)

(3 a + 3 b) (7 a - 5 b)

5 - 24

∣ 3 ∣ - ∣ - 1 ∣

- \frac{- 12}{4}

What is expand (x+1)(2x^2-2)(x^3+5) ?
The solution to expand (x+1)(2x^2-2)(x^3+5) is 2x^6+2x^5-2x^4+8x^3+10x^2-10x-10