What is factor x^4-6x^3-8x^2+96x-128 ?

The solution to factor x^4-6x^3-8x^2+96x-128 is (x-2)(x-4)^2(x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^4-6x^3-8x^2+96x-128

factor

x^{4} - 6 x^{3} - 8 x^{2} + 96 x - 128

(x - 2) (x - 4)^{2} (x + 4)

Solution steps

x^{4} - 6 x^{3} - 8 x^{2} + 96 x - 128

Use the rational root theorem

= (x - 2) \frac{x ^{4} - 6 x ^{3} - 8 x ^{2} + 96 x - 128}{x - 2}

\frac{x ^{4} - 6 x ^{3} - 8 x ^{2} + 96 x - 128}{x - 2} = x^{3} - 4 x^{2} - 16 x + 64

= (x - 2) (x^{3} - 4 x^{2} - 16 x + 64)

Factor

x^{3} - 4 x^{2} - 16 x + 64 : (x - 4) (x + 4) (x - 4)

= (x - 2) (x - 4) (x + 4) (x - 4)

Apply exponent rule:

aa = a^{2}

(x - 4) (x - 4) = (x - 4)^{2}

= (x - 2) (x - 4)^{2} (x + 4)

m^{6} n - m^{2} n^{5}

\frac{2}{3 + 5}

24 x^{3} y^{4} - 18 x^{2} y^{5}

x^{2} + 12 x + 36 - 9 y^{2}

(- \frac{4}{5}) - \frac{7}{8}

What is factor x^4-6x^3-8x^2+96x-128 ?
The solution to factor x^4-6x^3-8x^2+96x-128 is (x-2)(x-4)^2(x+4)