What are the solutions to the equation 16x^2-4=0 ?

The solutions to the equation 16x^2-4=0 are x= 1/2 ,x=-1/2

Find the zeros of 16x^2-4=0

The zeros of 16x^2-4=0 are x= 1/2 ,x=-1/2

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16 x^{2} - 4 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

16 x^{2} - 4 = 0

Move

4

to the right side

16 x^{2} = 4

Divide both sides by

16

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

9 x + 4 = 2 x - 3

4 y^{3} + 12 y^{2} + 5 y

\frac{4 ^{\frac{7}{2}}}{3}

x^{2} - 1 = 80

\frac{x ^{- 3}}{x ^{- 5}}

What are the solutions to the equation 16x^2-4=0 ?
The solutions to the equation 16x^2-4=0 are x= 1/2 ,x=-1/2
Find the zeros of 16x^2-4=0
The zeros of 16x^2-4=0 are x= 1/2 ,x=-1/2