What are the solutions to the equation x^2-8x+16=25 ?

The solutions to the equation x^2-8x+16=25 are x=9,x=-1

Find the zeros of x^2-8x+16=25

The zeros of x^2-8x+16=25 are x=9,x=-1

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x^{2} - 8 x + 16 = 25

x = 9, x = - 1

Solution steps

x^{2} - 8 x + 16 = 25

Move

25

to the left side

x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 1}

x = \frac{- ( - 8 ) + 10}{2 \cdot 1} : 9

x = \frac{- ( - 8 ) - 10}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

x^{2} - 26 x + 25

\frac{( 2 x ^{2} ) ^{3} y ^{2}}{4 x ^{4} y ^{2}}

4 p q^{2} + 5 q r + 3 pq r

3 (y + 1) + 2 y = 5 (y - 1) + 5

(46.8)^{2} + (21.6)^{2} = c^{2}

What are the solutions to the equation x^2-8x+16=25 ?
The solutions to the equation x^2-8x+16=25 are x=9,x=-1
Find the zeros of x^2-8x+16=25
The zeros of x^2-8x+16=25 are x=9,x=-1