What is 3(2x^2-x+7)-(-x^2-3x+5) ?

The solution to 3(2x^2-x+7)-(-x^2-3x+5) is 7x^2+16

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simplify 3(2x^2-x+7)-(-x^2-3x+5)

simplify

3 (2 x^{2} - x + 7) - (- x^{2} - 3 x + 5)

7 x^{2} + 16

Solution steps

3 (2 x^{2} - x + 7) - (- x^{2} - 3 x + 5)

Apply the distributive law:

- (- a - b) = a + b

- (- x^{2} - 3 x + 5) = x^{2} + 3 x - 5

= 3 (2 x^{2} - x + 7) + x^{2} + 3 x - 5

Expand

3 (2 x^{2} - x + 7) : 6 x^{2} - 3 x + 21

= 6 x^{2} - 3 x + 21 + x^{2} + 3 x - 5

Group like terms

= 6 x^{2} + x^{2} - 3 x + 3 x + 21 - 5

Add similar elements:

6 x^{2} + x^{2} = 7 x^{2}

= 7 x^{2} - 3 x + 3 x + 21 - 5

Add similar elements:

- 3 x + 3 x = 0

= 7 x^{2} + 21 - 5

Subtract the numbers:

21 - 5 = 16

= 7 x^{2} + 16

24 ab x + 20 ab

6 (2 s + 4 s - 4) - 4 s

- 10 (x - 7) - 7 (x + 2)

a + \frac{a}{5} + \frac{2}{5} a

14 - ∣ - 10 + 3 ∣

What is 3(2x^2-x+7)-(-x^2-3x+5) ?
The solution to 3(2x^2-x+7)-(-x^2-3x+5) is 7x^2+16