What is (z^2z^4)/(z^3z^{-1)} ?

The solution to (z^2z^4)/(z^3z^{-1)} is z^4

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simplify (z^2z^4)/(z^3z^{-1)}

simplify

\frac{z ^{2} z ^{4}}{z ^{3} z ^{- 1}}

z^{4}

Solution steps

\frac{z ^{2} z ^{4}}{z ^{3} z ^{- 1}}

Simplify

z^{3} z^{- 1} : z^{2}

= \frac{z ^{2} z ^{4}}{z ^{2}}

Cancel the common factor:

z^{2}

= z^{4}

2 x (2 - 4 x + 3) + 3 (x + 4 y) - 8 x

\frac{5 12}{8}

4 x (3 x - 5)

\frac{y ^{3} y ^{4}}{y y ^{2}}

3 (- x)^{2}