What is ((-3ab^2)/(4bc^4))^3 ?

The solution to ((-3ab^2)/(4bc^4))^3 is -(27a^3b^3)/(64c^{12)}

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simplify ((-3ab^2)/(4bc^4))^3

simplify

(\frac{- 3 a b ^{2}}{4 b c ^{4}})^{3}

- \frac{27 a ^{3} b ^{3}}{64 c ^{12}}

Solution steps

(\frac{- 3 a b ^{2}}{4 b c ^{4}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( - 3 a b ^{2} ) ^{3}}{( 4 b c ^{4} ) ^{3}}

Simplify

(- 3 a b^{2})^{3} : - 27 a^{3} b^{6}

= \frac{- 27 a ^{3} b ^{6}}{( 4 b c ^{4} ) ^{3}}

Simplify

(4 b c^{4})^{3} : 64 b^{3} c^{12}

= \frac{- 27 a ^{3} b ^{6}}{64 b ^{3} c ^{12}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{27 a ^{3} b ^{6}}{64 b ^{3} c ^{12}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{b ^{6}}{b ^{3}} = b^{6 - 3}

= \frac{27 a ^{3} b ^{6 - 3}}{64 c ^{12}}

Subtract the numbers:

6 - 3 = 3

= - \frac{27 a ^{3} b ^{3}}{64 c ^{12}}

(2 a + 5)^{3}

(- 2) (- x) (x + 3)

(- \frac{1}{3}) + \frac{3}{8}

x^{2} - 12 x + 36 - 49 y^{2}

(2 + \frac{1}{3} (6 + h))^{2}

What is ((-3ab^2)/(4bc^4))^3 ?
The solution to ((-3ab^2)/(4bc^4))^3 is -(27a^3b^3)/(64c^{12)}