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Popular >

expand (1-2y)^4

Solution

expand

(1 - 2 y)^{4}

Solution

1 - 8 y + 24 y^{2} - 32 y^{3} + 16 y^{4}

Solution steps

(1 - 2 y)^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = 1, b = - 2 y

= i = 0 \sum 4 (i 4) \cdot 1^{(4 - i)} (- 2 y)^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} \cdot 1^{4} (- 2 y)^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} \cdot 1^{3} (- 2 y)^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} \cdot 1^{2} (- 2 y)^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} \cdot 1^{1} (- 2 y)^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} \cdot 1^{0} (- 2 y)^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} \cdot 1^{4} (- 2 y)^{0} : 1

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} \cdot 1^{3} (- 2 y)^{1} : - 8 y

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} \cdot 1^{2} (- 2 y)^{2} : 24 y^{2}

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} \cdot 1^{1} (- 2 y)^{3} : - 32 y^{3}

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} \cdot 1^{0} (- 2 y)^{4} : 16 y^{4}

= 1 - 8 y + 24 y^{2} - 32 y^{3} + 16 y^{4}

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Frequently Asked Questions (FAQ)

What is expand (1-2y)^4 ?
The solution to expand (1-2y)^4 is 1-8y+24y^2-32y^3+16y^4